Welcome to this tutorial post on palindrome strings in Java! In this article, we will explore the concept of palindromes, discuss what they are, and how to write a Java program to determine if a given string is a palindrome or not. We will use the BlueJ programming language for demonstration purposes. So, let’s dive right in!
Table of Contents
What is a Palindrome?
A palindrome refers to a word, phrase, number, or sequence of characters that maintains the same meaning when read forwards and backwards. In simpler terms, it remains unaltered even after its characters are reversed. For instance, words like “radar,” “madam,” and “level” exemplify palindromes.
Understanding the Program: Comparing Characters Logic
To check whether a given string is a palindrome, we will follow a simple approach using Java. The program will compare the characters at corresponding positions from the start and end of the string to determine if it is a palindrome or not. If all the characters match, the string is a palindrome; otherwise, it is not.
Program Code
public class PalindromeChecker
{
public static void main(String[] args) {
String input = "radar";
int i = 0;
int j = input.length() - 1;
boolean isPalindrome = true;
while (i < j) {
if (input.charAt(i) != input.charAt(j)) {
isPalindrome = false;
break;
}
i++;
j--;
}
if (isPalindrome) {
System.out.println(input + " is a palindrome.");
} else {
System.out.println(input + " is not a palindrome.");
}
}
}
Explanation of the Code
Let’s go through the code step by step to understand how it works:
- We start by defining a class called
PalindromeChecker
. - Inside the class, we have the
main
method, which serves as the entry point of our program. - We declare a variable called
input
and assign it the value “radar”. This is the string we want to check if it is a palindrome. - Next, we declare and initialize two integer variables,
i
andj
, with 0 and the length of theinput
string minus 1, respectively. These variables will be used to iterate through the string from both ends towards the middle. - We also declare a boolean variable called
isPalindrome
and set it totrue
. This variable will help us determine whether the input string is a palindrome or not. - We enter a
while
loop that continues until the value ofi
becomes greater than or equal toj
. This loop allows us to compare characters from the start and end of the string towards the middle. - Inside the loop, we use an
if
statement to check if the characters at positionsi
andj
in theinput
string are different. If the characters at positionsi
andj
are not equal, it indicates that the string does not qualify as a palindrome. - In that case, we set the value of
isPalindrome
tofalse
and exit the loop using thebreak
statement. - If the characters at positions
i
andj
are equal, we incrementi
and decrementj
to move on to the next pair of characters for comparison. - After the loop finishes, we reach the end of the
main
method. Here, we use anif-else
statement to check the value of theisPalindrome
variable. - If the value of
isPalindrome
istrue
, we print the message “radar is a palindrome.” This indicates that the input string “radar” is indeed a palindrome. - If the value of
isPalindrome
isfalse
, we print the message “radar is not a palindrome.” This indicates that the input string “radar” is not a palindrome.
And that’s it! The code efficiently determines whether a given string is a palindrome by comparing characters from both ends towards the middle.
Palindrome String Checking in Java: Reversing the String Logic
An alternative approach to identifying palindrome strings is by comparing the original string with its reversed counterpart, instead of matching characters at corresponding positions. If the reversed string matches the original string, it signifies that the input is a palindrome.
Program Code
public class PalindromeChecker {
public static void main(String[] args) {
String input = "radar";
String reversedInput = "";
// Reversing the input string
for (int i = input.length() - 1; i >= 0; i--) {
reversedInput += input.charAt(i);
}
if (input.equals(reversedInput)) {
System.out.println(input + " is a palindrome.");
} else {
System.out.println(input + " is not a palindrome.");
}
}
}
Explanation of the Code
- We start by defining a class called
PalindromeChecker
. - Inside the class, we have the
main
method, which serves as the entry point of our program. - We declare a variable called
input
and assign it the value “radar”. This is the string we want to check if it is a palindrome. - We also declare an empty string called
reversedInput
. This variable will store the reversed form of theinput
string. - Next, we use a
for
loop to iterate through the characters of theinput
string in reverse order. - Inside the loop, we append each character to the
reversedInput
string, effectively reversing the original string. - After the loop finishes, we use the
equals
method to compare the originalinput
string with thereversedInput
string. - If the two strings are equal, we print the message “radar is a palindrome.” This indicates that the input string “radar” is indeed a palindrome.
- If the two strings are not equal, we print the message “radar is not a palindrome.” This indicates that the input string “radar” is not a palindrome.
Conclusion
In this tutorial post, we explored the concept of palindrome strings in Java and discussed two different methods to check for palindromes. We examined the traditional approach of comparing characters at corresponding positions and the alternative approach of comparing the original string with its reversed form.
By leveraging the power of Java and the BlueJ programming language, we were able to demonstrate how to implement both methods and determine if a given string is a palindrome or not. Whether you choose to compare characters or compare the reversed string, both approaches provide effective ways to identify palindromes.
By utilizing the knowledge and code shared in this tutorial, you are now equipped with the tools to check for palindromes in Java. Feel free to explore further and experiment with different strings to deepen your understanding.
Happy coding!